Skip to product information
1 of 12

PayPal, credit cards. Download editable-PDF and invoice in 1 second!

GB/T 5750.12-2006 English PDF (GBT5750.12-2006)

GB/T 5750.12-2006 English PDF (GBT5750.12-2006)

Regular price $145.00 USD
Regular price Sale price $145.00 USD
Sale Sold out
Shipping calculated at checkout.
Quotation: In 1-minute, 24-hr self-service. Click here GB/T 5750.12-2006 to get it for Purchase Approval, Bank TT...

GB/T 5750.12-2006: Standard examination methods for drinking water -- Microbiological parameters

This standard specifies the use of plate counting method for the determination of total bacterial counts in drinking water and its source water. This method applies to the determination of total bacterial counts in drinking water and its source water.
GB/T 5750.12-2006
GB
NATIONAL STANDARD OF THE
PEOPLE REPUBLIC OF CHINA
ICS 13.060
C 51
Partially replacing GB/T 5750-1985
Standard examination methods for drinking water -
Microbiological parameters
ISSUED ON. DECEMBER 29, 2006
IMPLEMENTED ON. JULY 01, 2007
Issued by. Ministry of Health of the People's Republic of China;
Standardization Administration of the People's Republic of
China.
Table of Contents
Foreword . 3
1 Total bacterial count . 5
2 Total coliforms . 8
3 Thermotolerant coliform bacteria .. 25
4 Escherichia coli .. 29
5 Giardia .. 35
6 Cryptosporidium .. 55
Foreword
GB/T 5750 "Standard Test Method for Drinking Water" is divided into the following parts.
- General principles;
- Collection and preservation of water samples;
- Water analysis quality control;
- Organoleptic and physical parameters;
- Nonmetal parameters;
- Metal parameters;
- Aggregate organic parameters;
- Organic parameters;
- Pesticides parameters;
- Disinfection by-products parameters;
- Disinfectants parameter;
- Microbiological parameters;
- Radiological parameters.
This standard replaces total number of bacteria and total coliforms in the part II of GB/T 5750-1985 ?€?Standard examination methods for drinking water?€?.
As compared with GB/T 5750-1985, the main changes are as follows.
- ADJUST the structure in accordance with GB/T 1.1-2000 ?€?Directives for standardization - Part 1. Rules for the structure and drafting of standards?€?; - ADD 7 testing methods for 4 indicators including thermotolerant coliform bacteria, Escherichia coli, Giardia, and Cryptosporidium in drinking water.; This standard is proposed by and shall be under the jurisdiction of the Ministry of Health of the People's Republic of China.
The responsible drafting organizations of this standard. China Center for Disease Control and Prevention Safety Institute for Environment and Health- related Product.
Standard examination methods for drinking water -
Microbiological parameters
1 Total bacterial count
1.1 Plate counting method
1.1.1 Scope
This standard specifies the use of plate counting method for the determination of total bacterial counts in drinking water and its source water.
This method applies to the determination of total bacterial counts in drinking water and its source water.
1.1.2 Terms and definitions
The following terms and definitions apply to this standard.
1.1.2.1
Standard plate-count bacteria
The total number of bacteria contained in 1 mL of water sample obtained after 48 h incubation at 37??C under aerobic conditions on nutrient agar. 1.1.3 Culture media and reagents
1.1.3.1 Nutrient agar
1.1.3.1.1 Ingredients.
A Peptone 10 g
B Beef paste 3 g
C Sodium chloride 5 g
D Agar 10 g ~ 20 g
E Distilled water 1000 mL
1.1.3.1.2 Preparation method. After mixing above components, HEAT to
dissolve it, ADJUST the pH to 7.4 ~ 7.6, CONTAIN it into glass containers (if 1.1.5.2.3 USE the sterile pipette to take undiluted water samples and two ~ three 1 mL of water samples of the appropriate dilution degree, respectively INJECT it into the sterilized plate. The following operation is the same as the drinking water testing procedure.
1.1.6 Colony counting and reporting methods
When doing plate colony counting, it can use naked eye to directly observe it, if necessary, it shall make inspection with a magnifying glass to prevent omission. After recording the number of colonies in each plate, it shall calculate the average count of colonies in the same dilution, which is used for the calculation of next step. When obtaining the average of the dilutions, if one of the plates has more platelet-like colonies, it should not be used, but the plates without platelet colonies shall be used to calculate the average count of colonies of this dilution. If the platelet colonies are less than half of the plate, whilst the distribution of colony count on this other half is very even, the colonies of this half of plate is counted and multiplied by 2 to get the count of colonies of the entire plate. Then the average count of colonies of this dilution is calculated. 1.1.7 Selection and reporting methods for different dilutions
1.1.7.1 First SELECT the average count of colonies between 30 ~ 300 to make calculation, if the average count of colonies of only one dilution meet this range, then MULTIPLY the count of colonies by the dilution factor and REPORT it (SEE example 1 in Table 1).
1.1.7.2 If there are two dilutions, the count of colonies grown is between 30 ~ 300, it is determined depending on the ratio of the two, if the ratio is less than 2, it shall report the average of the two (such as example 2in Table 1). If the ratio is more than 2, it shall report the total count of colonies with a small dilution (example 3 in Table 1). If it is equal to 2, it shall also report the count of colonies of smaller dilution (SEE example 4 in Table 1).
1.1.7.3 If the average count of colonies of all dilutions is greater than 300, then it shall multiply the average count of colonies of the highest dilution by the dilution factor and report it (see Example 5 in Table 1).
1.1.7.4 If the average count of colonies of all dilutions is smaller than 30, then it shall multiply the average count of colonies of the lowest dilution by the dilution factor and report it (see Example 6 in Table 1).
1.1.7.5 If the average count of colonies of all dilutions is not between 30 ~ 300, then it shall multiply the average count of colonies closest to 30 or 300 by the dilution factor and report it (see Example 7 in Table 1).
1.1.7.6 If the plates of all dilutions are free from colony growth, it shall be reported as ?€?undetected?€?.
2.1.4.9 Small inverted tube.
2.1.4.10 Slides.
2.1.5 Testing procedure
2.1.5.1 Lactose fermentation test
2.1.5.1.1 TAKE 10 mL of water sample, INOCULATE it into 10 mL of double lactose peptone culture solution, TAKE 1 mL of water sample, INOCULATE it into 10 mL of single lactose peptone culture solution, TAKE another 1 mL of water sample, INJECT it into 9 mL of sterilized normal saline, MIX it uniformly, PIPETTE 1 mL (that is, 0.1 mL of water sample) into 10 mL single lactose peptone culture solution, INOCULATE 5 tubes for each dilution.
If the tap water that has been processed must be tested regularly or once a day, it can directly inoculate five sets of 10 mL water sample double culture medium, each set is inoculated with 10 mL of water sample.
2.1.5.1.2 When testing the source water, if the pollution is serious, it shall increase the dilution. It can inoculate 1, 0.1, 0.01 mL or even 0.1, 0.01, 0.001 mL. Each dilution is inoculated to 5 tubes, each water sample is totally inoculated to 15 tubes. When inoculating the water sample less than 1 mL, it must perform 10 times incremental dilution, take 1 mL for inoculation, and change one 1 mL sterile graduated pipette for each increment of dilution. 2.1.5.1.3 PLACE the inoculated tube in the incubator at 36 ??C ?? 1 ??C for 24 h ?? 2 h. If all lactose peptone culture tubes are not producing gas acid, then they can be reported as negative for the total coliforms. If they produce acid or gas, FOLLOW the steps below.
2.1.5.2 Separation culture
TRANSPLANT the fermentation tubes producing acid and gas onto the eosin methylene blue agar plate, CULTURE it in an incubator at 36 ??C ?? 1 ??C for 18 ~ 24 h. OBSERVE the colony morphology, SELECT the colonies with the
following characteristics for Gram staining, microscopic examination and confirmation test.
Dark purple black colonies with metallic luster;
Purple black colonies without or with slight metallic luster;
Pale purple colonies with darker color center.
2.1.5.3 Confirmation test
After the above stained microscopic examination, it is gram-negative bacillus, min per each sterilization. After the first two boiling, it is necessary to replace the water to rinse it for 2 ~ 3 times, to remove the residual solvent.
2.2.5.1.2 Filter sterilization. USE the ignited alcohol swab to perform flame sterilization, or USE steam sterilizer for autoclaving at 103.43 kPa (121 ??C, 15 lb) for 20 min.
2.2.5.2 Filtered water sample
USE the sterile tweezers to take the edge of the sterilized membrane filter, LET the rough surface face upwards, ATTACH it to the sterilized filter bed, FIX the filter, POUR 100 mL of water sample (if the water sample contains more
bacteria, it can reduce the filtered water sample volume or otherwise dilute the water sample) into the filter, OPEN the filter valve, PERFORM suction filtration at -5.07 ?? 104 Pa (minus 0.5 atmosphere).
2.2.5.3 Culture
After filtration of the water sample, MAKE suction for about another 5 s, CLOSE the filter valve, TAKE off the filter, USE sterile tweezers to take the edge of the membrane filter, TRANSFER it onto the magenta sodium sulfite medium, LET the bacteria catching face of the membrane filter face upwards, LET the membrane filter be in complete and close attachment with the culture medium, there shall be no air bubbles between them, INVERT the plate, PLACE it into the 37??C incubator to culture it for 24 h ?? 2 h.
2.2.6 Results observations and reports
2.2.6.1 SELECT colonies that meet the following characteristics for Gram staining and microscopic examination.
Purple red colonies with metallic luster;
Deep red colonies without or with slight metallic luster;
Pale red colonies with darker center.
2.2.6.1.1 The Gram-negative bacillus is further inoculated with lactose peptone culture solution, cultured at 37??C for 24 hours. If there is acid production and gas production, the total coliforms are determined to be positive.
2.2.6.1.2 CALCULATE the count of total coliforms growing on the mem...

View full details